(b+3)(b^2+2b-2)=

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Solution for (b+3)(b^2+2b-2)= equation: 


Simplifying
(b + 3)(b2 + 2b + -2) = 0

Reorder the terms:
(3 + b)(b2 + 2b + -2) = 0

Reorder the terms:
(3 + b)(-2 + 2b + b2) = 0

Multiply (3 + b) * (-2 + 2b + b2)
(3(-2 + 2b + b2) + b(-2 + 2b + b2)) = 0
((-2 * 3 + 2b * 3 + b2 * 3) + b(-2 + 2b + b2)) = 0
((-6 + 6b + 3b2) + b(-2 + 2b + b2)) = 0
(-6 + 6b + 3b2 + (-2 * b + 2b * b + b2 * b)) = 0
(-6 + 6b + 3b2 + (-2b + 2b2 + b3)) = 0

Reorder the terms:
(-6 + 6b + -2b + 3b2 + 2b2 + b3) = 0

Combine like terms: 6b + -2b = 4b
(-6 + 4b + 3b2 + 2b2 + b3) = 0

Combine like terms: 3b2 + 2b2 = 5b2
(-6 + 4b + 5b2 + b3) = 0

Solving
-6 + 4b + 5b2 + b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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